The initial value theorem lets you read off a signal’s value at directly from its Laplace transform, without inverting:
provided has no impulses at .
Why it works
For a unilateral transform , as the kernel concentrates more and more sharply at , so the integral approaches the initial value of . The factor of scales the kernel back to integral in the limit.
A non-rigorous but quick derivation: by the unilateral differentiation property, . Take on both sides. The left side goes to zero (the kernel vanishes for any fixed , leaving only a small contribution near from the jump ). The right side becomes . Equating: .
Worked example
The IVT requires to be strictly proper (numerator degree strictly less than denominator degree). If you try it on something improper like — same degrees — you get
which diverges. That’s the signature that contains an impulse at and the IVT doesn’t apply.
For a proper like :
So . Check: gives . ✓
When it’s useful
You’re given as a rational function and want the initial value of without bothering to invert. Common in checking solutions to ODE initial-value problems, or in characterizing step responses without computing the full time-domain function.
Conditions
- must have no impulse at (so must be a proper rational function).
- Either exists, or converges in some right half-plane.
For most engineering problems the conditions hold, and the IVT is a fast sanity check.
See also
The companion result for the long-time behavior is the Final value theorem, which gives — useful for finding the steady-state value of a system’s response.